Question

Один токарь выточил y деталей, другой на 7 деталей больше, чем первый, а третий на 8 деталей меньше, чем второй. Вместе они сделали 81 деталь. Решить уравнение.

Answer 1

У+(у+7)+(у+7-8)=81
3у+7-1=81
3у+6=81
3у=75
у=25

Answer 2

Пусть первый токарь выточил x деталей. Тогда второй токарь выточил (x + 7) деталей. И третий токарь выточил ((x + 7) - 8) = (x - 1) деталей. Всего они сделали 81 деталь, поэтому: x + (x + 7) + (x - 1) = 81 3x + 6 = 81 3x = 81 - 6 3x = 75 x = 75 / 3 x = 25 Таким образом, первый токарь выточил 25 деталей, второй - 32 детали (25 + 7), а третий - 24 детали (32 - 8).

Answer 3

Problem Analysis

We are given information about three lathe workers who have produced a total of 81 parts. The second worker has produced 7 more parts than the first worker, and the third worker has produced 8 fewer parts than the second worker. We need to find the number of parts produced by each worker.

Solution

Let's assume the number of parts produced by the first worker is x.

According to the given information: - The second worker has produced 7 more parts than the first worker, so the number of parts produced by the second worker is x + 7. - The third worker has produced 8 fewer parts than the second worker, so the number of parts produced by the third worker is (x + 7) - 8.

The sum of the parts produced by all three workers is 81, so we can write the equation:

x + (x + 7) + ((x + 7) - 8) = 81

Simplifying the equation: 3x + 6 = 81

Subtracting 6 from both sides: 3x = 75

Dividing both sides by 3: x = 25

Therefore, the first worker produced 25 parts, the second worker produced 25 + 7 = 32 parts, and the third worker produced 32 - 8 = 24 parts.

Answer

The first worker produced 25 parts, the second worker produced 32 parts, and the third worker produced 24 parts.