Question

При ремонте изделий из жести применяют сплав, содержащий 2 части свинца и 5 частей олова. Сколько граммов свинца и олова в отдельности содержится в 350 г сплава?

Answer 1

2+5=7 частей в сплаве
350:7=50 г приходится на одну часть
2*50=100 г свинца
5*50=250 г олова
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Answer 2

Calculating the Amount of Lead and Tin in the Alloy

To calculate the amount of lead and tin in the alloy, we can use the given ratio of 2 parts lead to 5 parts tin.

Let's denote the amount of lead as x grams and the amount of tin as y grams. According to the given ratio, we have the following equation:

x/y = 2/5

We also know that the total weight of the alloy is 350 grams, so we have:

x + y = 350

We can solve these two equations to find the values of x and y.

Solution

Using the given ratio, we can express x in terms of y as follows:

x = (2/5)y

Substituting this expression for x into the equation x + y = 350, we get:

(2/5)y + y = 350

Solving for y: (7/5)y = 350 y = (5/7) * 350 y = 250 grams

Substituting y = 250 into the equation x + y = 350: x + 250 = 350 x = 350 - 250 x = 100 grams

Answer

Therefore, in the 350-gram alloy, there are 100 grams of lead and 250 grams of tin.

This information is based on mathematical calculations and does not require external sources for verification.