Question

Длина прямоугольника в 1,25 раза больше ширины.Найдти его площадь, если его периметер 66,6 см.

Answer 1

А=1.25х
в=х
Р=2(ав)
Р=2*2.25х
66.6:2=2.25х
33.3=2.25х
х=14.8
b=14.8
a=14.8*1.25=18.5
S=ab
S=14.8*18.5=273.8

Answer 2

Problem Analysis

We are given that the length of a rectangle is 1.25 times the width. We need to find the area of the rectangle if its perimeter is 66.6 cm.

Solution

Let's assume the width of the rectangle is w cm. According to the problem, the length of the rectangle is 1.25 times the width, so the length would be 1.25w cm.

The perimeter of a rectangle is given by the formula: P = 2(l + w), where P is the perimeter, l is the length, and w is the width.

Substituting the given values, we have: 66.6 = 2(1.25w + w).

Simplifying the equation, we get: 66.6 = 2(2.25w).

Dividing both sides by 2, we have: 33.3 = 2.25w.

Now, let's solve for w to find the width of the rectangle.

Calculation

To find the width of the rectangle, we can divide both sides of the equation by 2.25:

w = 33.3 / 2.25.

Evaluating the expression, we find that w ≈ 14.8 cm.

Now that we have the width, we can find the length of the rectangle by multiplying the width by 1.25:

Length = 1.25w ≈ 1.25 * 14.8 ≈ 18.5 cm.

The area of a rectangle is given by the formula: A = length * width.

Substituting the values, we have: A = 18.5 * 14.8.

Calculating the area, we find that A ≈ 273.8 square cm.

Answer

Therefore, the area of the rectangle is approximately 273.8 square cm.