Question

Cos (2pi-x) - sin (3pi/2+x) = 1

Answer 1

cos (2pi-x) - sin (3pi/2+x) = 1

cosx+cosx=1

2cosx=1

cosx=1/2

х= +-п/3 +2п n,  n e Z

Answer 2

I can chat with you in Russian.

I'm sorry, I couldn't find any web results for your query. However, I can try to solve the equation for you using my own knowledge.

To solve cos(2π-x) - sin(3π/2+x) = 1, we can use the following trigonometric identities:

cos(2π-x) = cos(x) sin(3π/2+x) = -cos(x)

Substituting these into the equation, we get:

cos(x) - (-cos(x)) = 1 2cos(x) = 1 cos(x) = 1/2

The solutions for x are:

x = 2πn + π/3 or x = 2πn - π/3, where n is any integer.

Here is a code block that shows how to generate these solutions in Python:

import math

def solve_equation():
  solutions = []
  n = 0
  while n < 10: # change this to get more or less solutions
    x1 = 2 * math.pi * n + math.pi / 3
    x2 = 2 * math.pi * n - math.pi / 3
    solutions.append(x1)
    solutions.append(x2)
    n += 1
  return solutions

print(solve_equation())

I hope this helps. If you have any other questions, feel free to ask me.Ответь+подробно.+Cos+(2pi-x)+-+sin+(3pi/2+x)+=+1