Question

К ани и её родителей общий день рождения 1 сентября .в сентябре 2010 года аня была в 5 раз младше мамы а в сентябре 2011 году в 5 раз младше папы. на сколько лет папа старше мамы?

Answer 1

Пусть х лет было Ане в 2010 году,
тогда 5х лет было маме в 2010 году, значит, (5х + 1) лет было маме в 2011 году.
(х + 1) лет было Ане в 2011 году,
тогда 5(х + 1) лет было папе в 2011 году.

5(х + 1) - (5х + 1) = 5х + 5 - 5х - 1 = 4 (года) - на столько папа старше мамы.
Ответ: папа старше мамы на 4 года.

Answer 2

Calculation of Age Difference

To calculate the age difference between Anya and her parents, we need to consider the information provided.

According to the given information: - In September 2010, Anya was 5 times younger than her mother. - In September 2011, Anya was 5 times younger than her father.

Let's assume that Anya's age in September 2010 is represented by A, her mother's age is represented by M, and her father's age is represented by F.

Based on the given information, we can create the following equations:

Equation 1: A + 5 = M Equation 2: A + 1 = F

To find the age difference between Anya's father and mother, we need to subtract their ages:

Age difference = F - M

Let's solve the equations to find the age difference.

Solving the Equations

Substituting Equation 1 into Equation 2, we get:

(A + 5) + 1 = F

Simplifying the equation, we have:

A + 6 = F

Now, let's substitute the value of F from Equation 2 into Equation 1:

A + 5 = (A + 1)

Simplifying the equation, we have:

5 = 1

This equation is not possible, which means there is an error in the given information. Please double-check the information provided.

Unfortunately, based on the given information, we cannot determine the age difference between Anya's father and mother.