Question

1)9a-150/4=-15 2)2m/5=16/5 3)-3(a-1)-24=3 4)c+9/2=c+27/14 5)4y+4=-20 6)x/3-2=x-3/6 7)7y/9=14/3

Answer 1

Відповідь:1) 9а-150/4=15

9а-150=15•4

9а=60+150

а=210/9

а=23 1/3

2) 2m/5=16/5

10m=80

m=8

3) -3(a-1)-24=3

-3a+3=27

-3a=24

a=-8

4) c+9/2=c+27/14

(c+9)•14=(c+27)•2

14c+126=2c+54

14c-2c=54-126

12c=72c=6

5)4y+4=20

4y=-24

y=-6

6) x/3-2=x-3/6

6x=(x-3)•(3-2)

6x=3x+6-2x-9

6x-3x+2x=-3

5x=-3

x=-3/5

7) 7y/9=14/3

21y=126

y=6

Покрокове пояснення:

Answer 2

Let's solve each equation step by step:

1. $9a - \frac{150}{4} = -15$

   Multiply both sides by 4 to get rid of the fraction: $4 \cdot 9a - 150 = -15 \cdot 4$

   Simplify: $36a - 150 = -60$

   Add 150 to both sides: $36a = 90$

   Divide by 36: $a = \frac{90}{36} = \frac{5}{2}$

2. $\frac{2m}{5} = \frac{16}{5}$

   Multiply both sides by 5 to get rid of the fraction: $5 \cdot \frac{2m}{5} = 5 \cdot \frac{16}{5}$

   Simplify: $2m = 16$

   Divide by 2: $m = 8$

3. $-3(a - 1) - 24 = 3$

   Distribute the -3 on the left side: $-3a + 3 - 24 = 3$

   Combine like terms: $-3a - 21 = 3$

   Add 21 to both sides: $-3a = 24$

   Divide by -3: $a = -8$

4. $\frac{c + 9}{2} = \frac{c + 27}{14}$

   Cross-multiply: $14(c + 9) = 2(c + 27)$

   Simplify: $14c + 126 = 2c + 54$

   Subtract 2c from both sides: $12c + 126 = 54$

   Subtract 126 from both sides: $12c = -72$

   Divide by 12: $c = -6$

5. $4y + 4 = -20$

   Subtract 4 from both sides: $4y = -24$

   Divide by 4: $y = -6$

6. $\frac{x}{3} - 2 = \frac{x - 3}{6}$

   Multiply both sides by 6 to get rid of the fraction: $6 \cdot \left(\frac{x}{3} - 2\right) = 6 \cdot \frac{x - 3}{6}$

   Simplify: $2x - 12 = x - 3$

   Add 12 to both sides: $2x = x + 9$

   Subtract x from both sides: $x = 9$

7. $\frac{7y}{9} = \frac{14}{3}$

   Cross-multiply: $3 \cdot 7y = 9 \cdot 14$

   Simplify: $21y = 126$

   Divide by 21: $y = 6$