Question

1-(6 2/5-5 3/5) 4+(5 7/9-3 1/9) 14 7/11+(22 4/11-19) 30-(4 3/7+6/7) 2/15+(7/15+3 8/15) 41 2/9-(27-5/9)

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

Let's simplify each of these expressions step by step:

1. $1 - (6 \frac{2}{5} - 5 \frac{3}{5})$

   First, subtract the fractions inside the parentheses: $6 \frac{2}{5} - 5 \frac{3}{5} = \left(6 - 5\right) + \left(\frac{2}{5} - \frac{3}{5}\right) = 1 - \frac{1}{5} = \frac{4}{5}$

   Now, substitute this back into the original expression: $1 - \frac{4}{5} = \frac{5}{5} - \frac{4}{5} = \frac{1}{5}$

2. $4 + (5 \frac{7}{9} - 3 \frac{1}{9})$

   Similarly, subtract the fractions inside the parentheses: $5 \frac{7}{9} - 3 \frac{1}{9} = \left(5 - 3\right) + \left(\frac{7}{9} - \frac{1}{9}\right) = 2 + \frac{6}{9} = 2 + \frac{2}{3}$

   Now, substitute this back into the original expression: $4 + 2 + \frac{2}{3} = 6 + \frac{2}{3}$

3. $14 \frac{7}{11} + (22 \frac{4}{11} - 19)$

   Subtract the whole numbers inside the parentheses: $22 \frac{4}{11} - 19 = \left(22 - 19\right) + \frac{4}{11} = 3 + \frac{4}{11}$

   Now, substitute this back into the original expression: $14 \frac{7}{11} + 3 + \frac{4}{11} = 17 + \frac{4}{11}$

4. $30 - (4 \frac{3}{7} + \frac{6}{7})$

   First, add the fractions inside the parentheses: $4 \frac{3}{7} + \frac{6}{7} = \left(4 + \frac{6}{7}\right) + \frac{3}{7} = \frac{34}{7} + \frac{3}{7} = \frac{37}{7}$

   Now, substitute this back into the original expression: $30 - \frac{37}{7}$

5. $\frac{2}{15} + \left(\frac{7}{15} + 3 \frac{8}{15}\right)$