Question

(1\3х-1\7)*(3,9+1,3х)=0

Answer 1

Ответ:

x1= -3

x2= 3/7

Пошаговое объяснение:

(1/3x-1/7)*(3.9+1.3x)=0

(1/3x-1/7)*(39/10+13/10x)=0

1/3x-1/7x=0

39/10+13/10=0

x1= -3

x2= 3/7

Answer 2

To solve the equation $\left(\frac{1}{3}x - \frac{1}{7}\right) \left(3.9 + 1.3x\right) = 0$, we can use the zero-product property, which states that if the product of two factors is equal to zero, then at least one of the factors must be equal to zero. So, we set each factor equal to zero and solve for $x$:

1. Set $\frac{1}{3}x - \frac{1}{7} = 0$: $\frac{1}{3}x = \frac{1}{7}$

   Now, multiply both sides by 3 to isolate $x$: $x = \frac{1}{7} \times 3$ $x = \frac{3}{7}$

2. Set $3.9 + 1.3x = 0$: $1.3x = -3.9$

   Now, divide both sides by 1.3 to isolate $x$: $x = \frac{-3.9}{1.3}$ $x = -3$

So, the solutions to the equation are $x = \frac{3}{7}$ and $x = -3$.