Question

(5y +7) (2 y - 0,4)=a​

Answer 1

$10y^{2} -2y+14y-2,8=a\\10y^{2}+12y-2,8=a\\a=10y^{2}+12y-2,8\\a=10y^{2}+12y-2,8$

y∈R

Answer 2

To solve the equation (5y + 7)(2y - 0.4) = a, you can follow these steps:

1. Distribute the terms on the left-hand side of the equation: (5y + 7)(2y - 0.4) = a 10y^2 - 2y - 1.6 = a

2. Move 'a' to the right-hand side of the equation: 10y^2 - 2y - 1.6 - a = 0

Now, you have a quadratic equation in terms of 'y'. If you have a specific value for 'a,' you can solve for 'y' using the quadratic formula:

The quadratic formula is: y = (-b ± √(b² - 4ac)) / (2a)

In this equation:

• a = 10
• b = -2
• c = -1.6 - a (Replace 'a' with the specific value you have)

Now, plug these values into the quadratic formula and solve for 'y' by taking both the positive and negative square roots:

y = (-(-2) ± √((-2)² - 4(10)(-1.6 - a))) / (2(10))

Simplify and solve for 'y' for both roots:

1. y₁ = (2 + √(4 + 40(1.6 + a))) / 20
2. y₂ = (2 - √(4 + 40(1.6 + a))) / 20

These are the solutions for 'y' in terms of 'a' for the given equation.