Question

1)3(9+x)-6(x-3)=0 2)2x+4(8-x)=2​

Answer 1

Ответ:

1. 3(9+х)-6(х-3) =0

27+3х-6х+18=0

45-3х=0

-3х=-45

х=15

2. 2х+4(8-х) =2

2х+32-4х=2

-2х+32=2

-2=2-32

-2х=-30

х=15

Answer 2

To solve these equations, you'll need to isolate the variable 'x' in each equation. Let's go step by step:

1. 3(9 + x) - 6(x - 3) = 0

First, distribute the numbers on the left side of the equation:

27 + 3x - 6x + 18 = 0

Combine like terms:

27 - 3x + 18 = 0

Now, subtract 27 and 18 from both sides to isolate 'x':

-3x = -27 - 18

-3x = -45

To solve for 'x', divide both sides by -3:

x = -45 / -3 x = 15

So, the solution to the first equation is x = 15.

2. 2x + 4(8 - x) = 2

First, distribute the 4 on the left side of the equation:

2x + 32 - 4x = 2

Combine like terms:

2x - 4x + 32 = 2

Now, combine the 'x' terms:

-2x + 32 = 2

Subtract 32 from both sides to isolate 'x':

-2x = 2 - 32

-2x = -30

To solve for 'x', divide both sides by -2:

x = -30 / -2 x = 15

So, the solution to the second equation is also x = 15.