Question

Ширина поямоугльника 6 см а длина на 2 см больше. найди его периметр и площадь

Answer 1

Длина = 2+6 = 8
Периметр =(8+6)*2=14*2=28
Площадь = 8*6=48

*- умножить

Answer 2

Problem Statement

You have a rectangle with a width of 6 cm and a length that is 2 cm longer than the width. You need to find the perimeter and area of the rectangle.

Solution

To find the perimeter of a rectangle, you add up the lengths of all its sides. The formula for the perimeter of a rectangle is: P = 2 * (a + b), where P is the perimeter, a is the width, and b is the length.

To find the area of a rectangle, you multiply its length by its width. The formula for the area of a rectangle is: S = a * b, where S is the area, a is the width, and b is the length.

Let's calculate the perimeter and area of the given rectangle.

Calculation

Given: - Width (a) = 6 cm - Length (b) = 2 cm longer than the width

To find the length, we add 2 cm to the width: b = a + 2.

Substituting the values, we have: - Width (a) = 6 cm - Length (b) = 6 cm + 2 cm = 8 cm

Now, let's calculate the perimeter and area.

Perimeter (P): - P = 2 * (a + b) - P = 2 * (6 cm + 8 cm) - P = 2 * 14 cm - P = 28 cm

Area (S): - S = a * b - S = 6 cm * 8 cm - S = 48 cm^2

Therefore, the perimeter of the rectangle is 28 cm and the area is 48 cm^2.