Question

(3 (x+3) + 4y - 4=0.4x -3(y+2) - 4 = 0.​

Answer 1

Ответ:

1)3(x+1)

2)4x-3y-10

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Answer 2

To solve the system of equations:

1. $3(x + 3) + 4y - 4 = 0.4x - 3(y + 2) - 4 = 0$,

you can use the method of substitution or elimination. I'll demonstrate the elimination method here.

First, simplify both equations:

Equation 1: $3(x + 3) + 4y - 4 = 0.4x - 3(y + 2) - 4$

Expand and simplify:

$3x + 9 + 4y - 4 = 0.4x - 3y - 6 - 4$

Now, combine like terms:

$3x + 4y + 5 = 0.4x - 3y - 10$

Equation 2: $3x + 4y + 5 = 0.4x - 3y - 10$

Now, let's move all the terms to one side of each equation to set them equal to 0:

Equation 1: $3x + 4y + 5 - 0.4x + 3y + 10 = 0$

Simplify:

$2.6x + 7y + 15 = 0$

Equation 2: $3x + 4y + 5 - 0.4x + 3y + 10 = 0$

Simplify:

$2.6x + 7y + 15 = 0$

Now, you have a system of two equations:

1. $2.6x + 7y + 15 = 0$

Since both equations are identical, they represent the same line in the xy-plane. This means there are infinitely many solutions, and any point on the line $2.6x + 7y + 15 = 0$ is a solution to the system of equations.