Question

А) 6у + 3у = (6 + 3)у = 9у Б) 2а ∙ 3 ∙ 4 = (2 ∙ 3 ∙ 4)а = 24а

Answer 1

Ответ:

на фото

Пошаговое объяснение:

подпишись если не сложно цель 50 подписчиков удачи ;)

Answer 2

It seems like you're demonstrating some basic algebraic operations. Let me confirm and explain the steps for each expression you provided:

А) $6u + 3u = (6 + 3)u = 9u$

In this step, you're adding $6u$ and $3u$ together, which gives $9u$. Then, you factor out the $u$ from the sum of the coefficients, which is $6 + 3 = 9$, resulting in $9u$.

Б) $2a \times 3 \times 4 = (2 \times 3 \times 4) \times a = 24a$

Here, you're multiplying $2a$, $3$, and $4$ together, resulting in $24a$. Then, you're factoring out $a$ from the product of the coefficients, which is $2 \times 3 \times 4 = 24$, resulting in $24a$.

Both expressions demonstrate basic algebraic rules of combining like terms and factoring out common factors. Is there anything specific you'd like to ask about these expressions or algebra in general?