Question

2-3x=2(1-y), x(x+y)=12

Answer 1

Ответ:

можно лучший можно лучший можно лучший

Answer 2

1)2-3х=2(1-у)
2-3х=2-2у
-3х=-2у
Х=2/3у


2)это не знаю сори

Answer 3

To solve the system of equations:

1. 2 - 3x = 2(1 - y)
2. x(x + y) = 12

You can start by solving one of the equations for one variable and then substituting it into the other equation. Let's start by solving equation (1) for y:

1. 2 - 3x = 2(1 - y)

First, distribute the 2 on the right side:

2 - 3x = 2 - 2y

Now, isolate the term with y on the right side:

-3x + 2y = 2 - 2

-3x + 2y = 0

Next, solve equation (2) for y:

2. x(x + y) = 12

Distribute x on the left side:

x^2 + xy = 12

Now, isolate the term with y on the left side:

xy = 12 - x^2

Now, you can substitute the expression for xy from equation (2) into equation (1):

-3x + 2(12 - x^2) = 0

Now, distribute the 2 on the left side:

-3x + 24 - 2x^2 = 0

To simplify further, move all terms to one side of the equation:

2x^2 - 3x + 24 = 0

Now, you have a quadratic equation. You can try to solve this quadratic equation using the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this case, a = 2, b = -3, and c = 24. Plugging these values into the quadratic formula:

x = (-(-3) ± √((-3)² - 4(2)(24))) / (2(2))

x = (3 ± √(9 - 192)) / 4

Since the discriminant (the value inside the square root) is negative (9 - 192 < 0), there are no real solutions for x. This means the system of equations has no real solutions.

If you want to find complex solutions, you can continue using the quadratic formula, but the solutions will involve imaginary numbers.