Question

(4 1/3-3 4/9)² ×(2 1/4)²​

Answer 1

1)4 1/3-3 4/9= 8/9

2)8/9^2=)(8^2)/(9^2)=64/81

3)(2 1/4)^2=(9^2/4^2)=81/16

4)64/81*81/16=4

ОТВЕТ:4

Answer 2

Let's break this down step by step.

First, let's simplify the expressions inside the parentheses:

$4 \frac{1}{3} = \frac{13}{3}$ (mixed fraction converted to an improper fraction)

$3 \frac{4}{9} = \frac{31}{9}$ (mixed fraction converted to an improper fraction)

Now, let's subtract these fractions:

$\frac{13}{3} - \frac{31}{9}$

To subtract fractions, we need a common denominator, which in this case is 9:

$\frac{39}{9} - \frac{31}{9} = \frac{8}{9}$

Now, let's square $\frac{8}{9}$:

$\left(\frac{8}{9}\right)^2 = \frac{64}{81}$

Next, let's convert $2 \frac{1}{4}$ to an improper fraction:

$2 \frac{1}{4} = \frac{9}{4}$

Now, let's square $\frac{9}{4}$:

$\left(\frac{9}{4}\right)^2 = \frac{81}{16}$

Finally, let's multiply $\frac{64}{81}$ and $\frac{81}{16}$:

$\frac{64}{81} \times \frac{81}{16} = \frac{64 \times 81}{81 \times 16} = \frac{64}{16} = 4$