Question

Слиток серебра объем 70см имеет массу 735г какова масса слитка серебра объема 25см каков объем слитка серебра массой 420г

Answer 1

735 г:70 см3=10,5 г/см3 (плотность) (весит 1 см3 серебра)
10,5 г/см3*25 см3=262,5 г (весит слиток объемом 25 см3)
420 г:10,5 г/см3=40 см3 (объем слитка массой 420 г)
Ответ: слиток объемом 25 см3 весит 262,5 г, а слиток массой 420 г имеет объем 40 см3

см3 - это см в кубе

Answer 2

Calculation of Silver Ingot Mass and Volume

To calculate the mass of a silver ingot with a volume of 25 cm³ and the volume of a silver ingot with a mass of 420g, we can use the given information about the silver ingot with a volume of 70 cm³ and a mass of 735g.

Let's start by finding the mass of the silver ingot with a volume of 25 cm³.

1. Mass of Silver Ingot with Volume of 25 cm³:

Using the given information about the silver ingot with a volume of 70 cm³ and a mass of 735g, we can use the concept of density to find the mass of the silver ingot with a volume of 25 cm³.

The formula for density is: \[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]

We can rearrange this formula to solve for mass: \[ \text{Mass} = \text{Density} \times \text{Volume} \]

Given: - Volume of the silver ingot = 70 cm³ - Mass of the silver ingot = 735g

Using the density formula, we can calculate the density of the silver ingot: \[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} = \frac{735g}{70cm³} \]

Now, we can use the density to find the mass of the silver ingot with a volume of 25 cm³: \[ \text{Mass} = \text{Density} \times 25cm³ \]

2. Volume of Silver Ingot with Mass of 420g:

Similarly, we can use the given information to find the volume of the silver ingot with a mass of 420g.

Let's calculate the volume using the density formula: \[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]

Given: - Volume of the silver ingot = ? - Mass of the silver ingot = 420g

We can rearrange the density formula to solve for volume: \[ \text{Volume} = \frac{\text{Mass}}{\text{Density}} \]

Now, we can use the density to find the volume of the silver ingot with a mass of 420g: \[ \text{Volume} = \frac{420g}{\text{Density}} \]

Let's calculate the mass of the silver ingot with a volume of 25 cm³ and the volume of the silver ingot with a mass of 420g using the density calculated from the given information.