Question

4/7(х-1)=2/7+х -2(х+3)=2х-1. ​

Answer 1

Ответ:

4/7(х-1)=2/7+х

(4/7)x - 4/7 = 2/7 + x

x - (4/7)x = -4/7 - 2/7

(3/7)x = -6/7

x = -6/7 * 7/3

x = -2

-2(х+3)=2х-1.

-2x - 6 = 2x - 1

2x + 2x = -6 + 1

4x = -5

x = -5 : 4

x = -1 1/4

Answer 2

To solve the system of equations:

1. 4/7(x-1) = 2/7 + x

First, let's multiply both sides of the equation by 7 to get rid of the fractions:

4(x - 1) = 2 + 7x

Now, distribute the 4 on the left side:

4x - 4 = 2 + 7x

Next, move the 4x term to the right side of the equation by subtracting 4x from both sides:

-4 = 2 + 3x

Now, subtract 2 from both sides:

-6 = 3x

Finally, divide both sides by 3 to solve for x:

x = -6/3 x = -2

2. -2(x + 3) = 2x - 1

Let's distribute the -2 on the left side:

-2x - 6 = 2x - 1

Now, add 2x to both sides to move all the x terms to the left:

-6 = 4x - 1

Next, add 1 to both sides:

-5 = 4x

Now, divide both sides by 4 to solve for x:

x = -5/4

So, the solution to the system of equations is x = -2 and x = -5/4.