Question

-2(x+2)= 8-5x|3х+5|=7​

Answer 1

$1) \: - 2(x + 2) = 8 - 5x \\ - 2x - 4 = 8 - 5x \\ - 2x + 5x = 8 + 4 \\ 3x = 12 \\ \bf{x = 4} \\ \\ 2) \: |3x + 5| = 7 \\ 3x + 5 = 7 \: , \: 3x + 5 = - 7 \\ x = \frac{2}{3} \: , \: x = - 4 \\ \bf{ x_{1} = - 4 \: , \: x_{2} = \frac{2}{3} }$

Answer 2

Let's solve each equation separately:

1. Equation $-2(x + 2) = 8 - 5x$:

   Distribute the -2 on the left side:

   $-2x - 4 = 8 - 5x$

   Add $5x$ to both sides:

   $3x - 4 = 8$

   Add 4 to both sides:

   $3x = 12$

   Divide by 3:

   $x = 4$

2. Equation $|3x + 5| = 7$:

   Since the absolute value is equal to a positive number, we have two cases:

   a. $3x + 5 = 7$

   Subtract 5 from both sides:

   $3x = 2$

   Divide by 3:

   $x = \frac{2}{3}$

   b. $-(3x + 5) = 7$

   Distribute the negative sign:

   $-3x - 5 = 7$

   Add 5 to both sides:

   $-3x = 12$

   Divide by -3:

   $x = -4$

So, the solutions to the system of equations are $x = \frac{2}{3}$ and $x = -4$.