Question

а=60,а:6,а-а:6. а=24,а:6,а-а:6. а=36,а:6,а-а:6. а=54,а:6,а-а:6. а=42,а:6,а-а:6. а=48,а:6,а-а:6. а=6,а:6,а-а:6.

Answer 1

А=60 60:6=10, 60-60:6=0. а=24, 24:6=4, 24-24:6=0. а=36, 36:6=6, 36-36:6=0. а=54, 54:6=9, 54-54:6=0. а=42. 42:6=7, 42-42:6=0. а=48, 48:6=8, 48-48:6=0. а=6, 6:6=1, 6-6:6=0

Answer 2

It looks like you've provided a sequence of mathematical operations involving the variable "a". Each line seems to consist of three calculations:

1. Assigning a value to "a".
2. Dividing "a" by 6.
3. Subtracting the result of the division from the original value of "a".

I'll go through the calculations step by step using the provided values:

1. When a = 60:

   • a:6 = 60 / 6 = 10
   • a - a:6 = 60 - 10 = 50

2. When a = 24:

   • a:6 = 24 / 6 = 4
   • a - a:6 = 24 - 4 = 20

3. When a = 36:

   • a:6 = 36 / 6 = 6
   • a - a:6 = 36 - 6 = 30

4. When a = 54:

   • a:6 = 54 / 6 = 9
   • a - a:6 = 54 - 9 = 45

5. When a = 42:

   • a:6 = 42 / 6 = 7
   • a - a:6 = 42 - 7 = 35

6. When a = 48:

   • a:6 = 48 / 6 = 8
   • a - a:6 = 48 - 8 = 40

7. When a = 6:

   • a:6 = 6 / 6 = 1
   • a - a:6 = 6 - 1 = 5

Each time, you're dividing "a" by 6 and then subtracting the result from the original value of "a". The pattern holds for all the provided values of "a".