Question

16х+16у+17х(квадрате)+17хуху+2у+3х+6ху+4у-2х-8

Answer 1

1) 17x(x+y)+16(x+y)=(x+y)(17x+16)
2) y(x+2)+3(x+2)=(x+2)(y+3)
3) y(x+4)-2(x+4)=(x+4)(y-2)

Answer 2

It looks like you've provided an expression with variables x, y, and квадрате (which I assume is meant to represent a squared term involving x). The expression you've given is:

16x + 16y + 17x^2 + 17xy^2 + 2y + 3x + 6xy + 4y - 2x - 8

If you'd like to simplify or perform any specific operations on this expression, please let me know!