Question

A+B+C=290 A+E+C=270 A+B+E=240 надо найти все значения

Answer 1

A=220; B=20; C=50; E=0. На фото расчёт, ну, думаю, мало вероятно, что кто-то поймёт.

Answer 2

To find all the values, we can set up a system of equations based on the given information:

Let A, B, C, D, and E be the values we want to find.

1. A + B + C = 290
2. A + E + C = 270
3. A + B + E = 240

Now, we can solve these equations simultaneously to find the values of A, B, C, D, and E.

To do that, we can perform some algebraic operations on the equations:

1. A + B + C = 290
2. A + E + C = 270
3. A + B + E = 240

Now, let's try to eliminate variables to find the value of A:

Subtract equation (3) from equation (1):

(A + B + C) - (A + B + E) = 290 - 240 C - E = 50 ...........(4)

Now, subtract equation (3) from equation (2):

(A + E + C) - (A + B + E) = 270 - 240 C - B = 30 ...........(5)

Now, we have two equations (4 and 5) with only two variables (C and E). We can solve them simultaneously:

Adding equation (4) and equation (5):

(C - E) + (C - B) = 50 + 30 2C - (E + B) = 80 2C - E - B = 80 ...........(6)

We know that A + B + C = 290 (from equation 1).

Now, substitute the value of C from equation (6) into the equation above:

A + B + (2C - E - B) = 290 A + 2C - E = 290 ...........(7)

Now, we have two equations (6 and 7) with only two variables (A and C). We can solve them simultaneously:

Subtract equation (6) from equation (7):

(A + 2C - E) - (2C - E - B) = 290 - 80 A + B = 210 ...........(8)

Now, we have two equations (5 and 8) with only two variables (A and B). We can solve them simultaneously:

Subtract equation (5) from equation (8):

(A + B) - (C - B) = 210 - 30 A + 2B = 180

Now, we can find the value of B:

A + 2B = 180 2B = 180 - A B = (180 - A)/2 ...........(9)

Now, we can find the value of C using equation (5):

C - B = 30 C = B + 30

Now, we can find the value of C using equation (9):

C = (180 - A)/2 + 30

Now, let's consider equation (8):

A + B = 210

Substitute the value of B from equation (9):

A + (180 - A)/2 = 210

Solve for A:

2A + 180 - A = 420 A = 420 - 180 A = 240

Now that we have the value of A, we can find the value of B:

B = (180 - A)/2 B = (180 - 240)/2 B = (-60)/2 B = -30

Next, let's find the value of C:

C = (180 - A)/2 + 30 C = (180 - 240)/2 + 30 C = (-60)/2 + 30 C = -30 + 30 C = 0

Now, we can find the value of E using equation (4):

C - E = 50 0 - E = 50 E = 0 - 50 E = -50

So, the values of A, B, C, D, and E are:

A = 240 B = -30 C = 0 D = Not enough information provided to determine its value. E = -50