Question

Сократить 207/920 но несократимой дроби.

Answer 1

НОД(207;920)=НОД(3*69;2*460)=НОД(3*3*23;2*2*2*115)=НОД(3*3*23;2*2*2*5*23)=23
$\frac{207}{920}= \frac{3*3}{2*2*2*5}= \frac{9}{40}$

Answer 2

207/920=207:23/920:23=9/40

Answer 3

To simplify the fraction 207/920, we need to find the greatest common divisor (GCD) of the numerator (207) and the denominator (920) and then divide both by this GCD. If the resulting fraction is still not simplified (i.e., it's not in its simplest form), then the original fraction is irreducible, as there is no greater common factor to cancel out.

The GCD of 207 and 920 is 23 (calculated by finding the largest number that divides both 207 and 920 without leaving a remainder).

Now, we divide both the numerator and the denominator by 23:

207 ÷ 23 = 9 920 ÷ 23 = 40

So, the simplified fraction is 9/40, and it is not reducible any further.