
X+10 x=10,20,6,30 как это делать


Ответы на вопрос

10+10=20
20+10=30
6+10=16
30+10=40



х+10
Если х=10, то:
10+10=20
Если х=20, то:
20+10=30
Если х=6, то:
6+10=16
Если х=30, то:
30+10=40



To solve the equation x + 10x = 10, 20, 6, 30, you need to find the value of x that satisfies the equation.
First, let's rewrite the equation as a quadratic equation: x + 10x = 10x^2 + 1x = 10, 20, 6, 30
Now, we have four different equations to solve for x:
- 10x^2 + x = 10
- 10x^2 + x = 20
- 10x^2 + x = 6
- 10x^2 + x = 30
Let's solve each equation one by one:
- 10x^2 + x = 10 To solve this equation, we can set it to 0 by subtracting 10 from both sides: 10x^2 + x - 10 = 0
Now, we can either factor this quadratic equation or use the quadratic formula to find the values of x. For this equation, we can factor it as follows: (2x - 1)(5x + 10) = 0
Setting each factor to zero and solving for x:
- 2x - 1 = 0 => 2x = 1 => x = 1/2
- 5x + 10 = 0 => 5x = -10 => x = -2
So, the solutions for the first equation are x = 1/2 and x = -2.
- 10x^2 + x = 20 Similar to the previous equation, we set it to 0: 10x^2 + x - 20 = 0
Again, we can factor this quadratic equation: (2x - 4)(5x + 5) = 0
Setting each factor to zero and solving for x:
- 2x - 4 = 0 => 2x = 4 => x = 2
- 5x + 5 = 0 => 5x = -5 => x = -1
So, the solutions for the second equation are x = 2 and x = -1.
- 10x^2 + x = 6 Setting it to 0: 10x^2 + x - 6 = 0
Factorizing: (2x - 1)(5x + 6) = 0
Solving for x:
- 2x - 1 = 0 => 2x = 1 => x = 1/2
- 5x + 6 = 0 => 5x = -6 => x = -6/5
So, the solutions for the third equation are x = 1/2 and x = -6/5.
- 10x^2 + x = 30 Setting it to 0: 10x^2 + x - 30 = 0
Factorizing: (2x - 3)(5x + 10) = 0
Solving for x:
- 2x - 3 = 0 => 2x = 3 => x = 3/2
- 5x + 10 = 0 => 5x = -10 => x = -2
So, the solutions for the fourth equation are x = 3/2 and x = -2.
In conclusion, the solutions to the original equation x + 10x = 10, 20, 6, 30 are: x = 1/2, x = -2, x = 2, x = -1, x = 3/2, x = -6/5.


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