Question

( 14y+21) (1, 8-0, 3y) =0

Answer 1

14y+21=0
14y=-21
y=-21/14
y=-3/2=-1,5

1,8-0,3y=0
0,3y=1,8
y=1,8/0,3
y=6

Answer 2

To solve the equation $(14y + 21)(1, 8 - 0, 3y) = 0$, we set the expression inside the parentheses equal to zero and solve for $y$:

$(14y + 21)(1 - 0.3y) = 0$

Now, we can apply the zero-product property, which states that if the product of two factors is equal to zero, then at least one of the factors must be equal to zero.

So, we have two cases to consider:

1. $14y + 21 = 0$

Let's solve for $y$ in this case:

$14y = -21$

Divide both sides by 14:

$y = -\frac{21}{14}$

Simplify the fraction:

$y = -\frac{3}{2}$

2. $1 - 0.3y = 0$

Let's solve for $y$ in this case:

Subtract 1 from both sides:

$-0.3y = -1$

Divide both sides by -0.3:

$y = \frac{-1}{-0.3}$

Simplify the fraction:

$y = \frac{10}{3}$

So, the solutions to the equation are $y = -\frac{3}{2}$ and $y = \frac{10}{3}$.