Question

А) 8у = –62,4 + 5у; б) 3/4×-2/3х+1=1/2×+1/6.

Answer 1

8y-5y=-62.4
3y=-62.4
y=-62.4:3
y=-20. 8
Ответ: - 20.8
Б)
3/4х-2/3х+1=1/2х+1/6
3/4х-2/3х-1/2х=1/6-1
-5/12х=-5/6
х=-5/6:(-5/12)
х=2
Ответ: 2

Answer 2

To solve the equations, let's find the values of the variables in each case:

а) 8у = –62.4 + 5у

Step 1: Get all the terms with 'у' on one side of the equation: Subtract 5у from both sides: 8у - 5у = -62.4

Step 2: Simplify the equation: 3у = -62.4

Step 3: Solve for 'у': Divide both sides by 3: у = -62.4 / 3 у = -20.8

So the value of 'у' is -20.8.

б) 3/4 × (-2/3)х + 1 = 1/2 × (1/6)

Step 1: Simplify both sides of the equation: (-2/3)х + 1 = (1/2) × (1/6)

Step 2: Calculate the right-hand side of the equation: (-2/3)х + 1 = 1/12

Step 3: Move the constant term (1) to the other side by subtracting it from both sides: (-2/3)х = 1/12 - 1

Step 4: Simplify the equation further: (-2/3)х = 1/12 - 12/12 (-2/3)х = -11/12

Step 5: Solve for 'х': Divide both sides by (-2/3), which is the same as multiplying by its reciprocal ( -3/2): х = (-11/12) × (-3/2) х = 33/24 х = 11/8

So the value of 'х' is 11/8.