Question

(5x+3)(4-2x)=0 20 баллов

Answer 1

20x+12-10x^2-6x=0
10x^2-14x-12=0
D=(-14)^2-10*4*(-12)=196+480=676
sqrt(D)=sqrt(676)=26
x1=14+26/20=40/20=2
x2=14-26/20=-12/20=-3/5=-0.6

Answer 2

To find the values of 'x' that satisfy the equation (5x+3)(4-2x) = 0, we need to set each factor equal to zero and solve for 'x'. The equation will be satisfied when either (5x+3) = 0 or (4-2x) = 0.

1. Set (5x+3) = 0 and solve for 'x': 5x + 3 = 0 5x = -3 x = -3/5

2. Set (4-2x) = 0 and solve for 'x': 4 - 2x = 0 -2x = -4 x = -4 / -2 x = 2

So, the solutions for 'x' are x = -3/5 and x = 2. These values make the expression (5x+3)(4-2x) equal to zero.