Question

X^2-2x-3=0 Дискименант подробно пж

Answer 1

Ответ на картинке внизу страницы

Answer 2

x^2-2x-3=0

a=1, b=-2, c=-3

D=(-2)^2-4*1*(-3)=4+12=16

x1=(2+√16)/2=(2+4)/2=3

x2=(2-√16)/2=(2-4)/2=-2/2=-1

Ответ: -1; 3.

Answer 3

To find the discriminant of a quadratic equation of the form $ax^2 + bx + c = 0$, the discriminant is given by the expression $D = b^2 - 4ac$. In your case, the quadratic equation is $x^2 - 2x - 3 = 0$.

Comparing it to the general form $ax^2 + bx + c = 0$, we have $a = 1$, $b = -2$, and $c = -3$. Now, we can calculate the discriminant:

$D = b^2 - 4ac$ $D = (-2)^2 - 4 \cdot 1 \cdot (-3)$ $D = 4 + 12$ $D = 16$

The discriminant is $16$. The discriminant is used to determine the nature of the roots of the quadratic equation:

1. If $D > 0$, the quadratic equation has two distinct real roots.
2. If $D = 0$, the quadratic equation has one real root (a repeated root).
3. If $D < 0$, the quadratic equation has two complex roots (conjugate pair).

In this case, since $D = 16 > 0$, the quadratic equation $x^2 - 2x - 3 = 0$ has two distinct real roots.