Question

3x(x+1)-2x(5x+3)<7 x(2-x)+4

Answer 1

3x(x+1)-2x(5x+3)-7x(2-x)-4<0
3x^2+3x-10x^2-5x-14x+7x^2-4-16x-4<0
Н.ф
-16х-4=0
-16x=4
X=4:(-16)
X=-0,25 :))

Answer 2

To solve the inequality 3x(x+1) - 2x(5x+3) < 7x(2-x) + 4, we'll first simplify the expression and then find the solution.

Step 1: Simplify the expression on both sides of the inequality.

3x(x+1) - 2x(5x+3) < 7x(2-x) + 4

Expand the products:

3x^2 + 3x - 10x^2 - 6x < 14x - 7x^2 + 4

Combine like terms:

(3x^2 - 10x^2) + (3x - 6x) < (14x - 7x^2) + 4

-7x^2 - 3x < 14x - 7x^2 + 4

Step 2: Eliminate the common terms with -7x^2:

-3x < 14x + 4

Step 3: Bring all the terms to one side:

-3x - 14x < 4

-17x < 4

Step 4: Divide by the coefficient of x, remembering to reverse the inequality since we're dividing by a negative number:

x > 4 / (-17)

x > -4/17

So the solution to the inequality is x > -4/17.