Question

(1/2;0)принадлежит y=4x²-4x+1

Answer 1

0=4*(1\2)²-4*1\2+1

0=4*1\4-2+1

0=1-2+1

0=0

(1\2;0)-принадлежит

Answer 2

To check if the point (1/2, 0) belongs to the graph of the function y = 4x² - 4x + 1, we need to substitute the x-coordinate (1/2) into the equation and check if the resulting y-coordinate is equal to 0.

Let's do the calculation:

y = 4(1/2)² - 4(1/2) + 1 y = 4(1/4) - 2 + 1 y = 1 - 2 + 1 y = 0

The y-coordinate of the point (1/2, 0) matches the result of the equation when x = 1/2. Therefore, the point (1/2, 0) does belong to the graph of the function y = 4x² - 4x + 1.