Question

(2-1)+(4-3)+...+(2014-2013)

Answer 1

Ответ:

1007

Пошаговое объяснение:

Сумма (2014/2)=1007 разностей(т.к. даются все числа подряд от 1 до 2014, всего их 2014, пар 2014/2), каждая из которых равна 1. 1007*1=1007

Answer 2

To compute the sum of the given series, we can simplify each pair in the parentheses first and then add them all together. The series consists of consecutive numbers, where each pair has a difference of 1. So, we can rewrite the series as:

(2 - 1) + (4 - 3) + (6 - 5) + ... + (2014 - 2013)

Now, we can calculate each term:

(2 - 1) = 1 (4 - 3) = 1 (6 - 5) = 1 ... (2014 - 2013) = 1

Since all the terms are 1, we can see that the sum of the entire series is simply the number of terms in the series, which is the same as the difference between the last term and the first term, plus 1. In this case, the last term is 2014, and the first term is 1.

Sum = (2014 - 1) + 1 = 2013 + 1 = 2014

So, the sum of the series (2-1)+(4-3)+...+(2014-2013) is 2014.