Question

Решите уравнение y=0 если y=2x^3-3x^2-36x+13=0

Answer 1

Ответ: x1  = −3.7548;  

            x2  = 4.9017;  

             х3  = 0.3532.

Пошаговое объяснение:

Для вычисления корней этого кубического уравнения использована тригонометрическая формула Виета. Решение  в приложении.

Answer 2

To solve the equation $y = 2x^3 - 3x^2 - 36x + 13 = 0$, we need to find the values of $x$ that make $y$ equal to zero.

Step 1: Set $y$ to zero and write the equation as a cubic equation:

$2x^3 - 3x^2 - 36x + 13 = 0$

Step 2: Try to factor the cubic equation. Unfortunately, in this case, it is not easily factorable.

Step 3: To find the solutions, we can use numerical methods or a graphing calculator to approximate the roots.

Using a graphing calculator or a software, we find the roots approximately:

$x \approx 5.37$

$x \approx -2.19$

$x \approx 0.82$

So, the solutions for $x$ are approximately $5.37$, $-2.19$, and $0.82$.