Question

4х+2у=92 х+у=33 и х+у=74 3х+5у=292

Answer 1

Ответ:

y=20 x=13

И

y=35 x=39

Пошаговое объяснение:

4(33-y)+2y=92

132-4y+2y=92

-2y=-40

y=20

x=33-20

И

3(74-у)+5y=292

222-3y+5y=292

2y=70

y=35

x=74-35

x=39

Answer 2

1) х=13 у=20
2)х=39 у=35

Answer 3

It seems like you've written down a system of equations with two variables (x and y). However, there's an inconsistency in the equations you provided. Specifically, you've written two equations that have the same left-hand side (x + y), but different right-hand sides. This would lead to an inconsistent system, as the same expression cannot have two different values simultaneously.

To clarify, here are the equations you provided:

1. 4x + 2y = 92
2. x + y = 33
3. x + y = 74
4. 3x + 5y = 292

Equation 2 and Equation 3 are conflicting, as they both state x + y equals different values (33 and 74, respectively). This means that there is no solution that satisfies all four equations simultaneously.

If you need assistance with a consistent system of equations or need further clarification, please provide the correct set of equations.