Question

Z1/z2=? Если z1=4+3i ; z2=-1-i (4+3i)/(-1-i)=?

Answer 1

(4+3i)/(-1-i)=(4+3i)(-1+i)/(-1-i)(-1+i)=

(-4+4i-3i+3i²)/((-1)²-i²)=

(-4+i-3)/(1+1)=(-7+i)/2=0,5i-3,5

Answer 2

To find the value of (4+3i)/(-1-i), you can use the concept of complex number division. The general formula for dividing two complex numbers z1 = a + bi and z2 = c + di is as follows:

(z1 / z2) = ((a + bi) * (c - di)) / (c^2 + d^2)

Let's apply this formula to the given values:

z1 = 4 + 3i z2 = -1 - i

Now, let's find the result:

(z1 / z2) = ((4 + 3i) * (-1 - i)) / ((-1)^2 + (-1)^2) = ((-4 - 3i) + (4i - 3i^2)) / (1 + 1) = ((-4 - 3i) + (4i + 3)) / 2 = (-1 + i) / 2

So, the value of (4+3i)/(-1-i) is (-1 + i) / 2.