Question

Y=(x-2)^2+3 график функций

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

Это правильный ответ ма

Answer 3

The given function is in the form of a quadratic equation, where Y is a function of x. It represents a parabola.

The general form of a quadratic equation is Y = ax^2 + bx + c, where a, b, and c are constants.

In this case, a = 1, b = -4, and c = 7. We can identify them from the given equation Y = (x - 2)^2 + 3.

Let's plot the graph of the function:

To do this, we'll choose some x values, calculate the corresponding Y values, and then plot the points on the graph.

Here's a table of values:

x	Y = (x-2)^2 + 3
0	7
1	4
2	3
3	4
4	7

Now, let's plot these points on the graph:

(Note: The graph is approximate and drawn manually.)

markdownCopy code
     |
  8  |       * 
     |          
  7  |      *   * 
     |    *       *
  6  |   *         
     | *           
  5  |             
     |              
  4  |            * 
     |          *  
  3  |         *   
     |        *    
  2  |        *    
     |         *   
  1  |          *  
     |           * 
  0  |_____________
     0   1   2   3   4

The graph is a parabola that opens upwards, and its vertex is at the point (2, 3). The parabola is symmetric about the vertical line x = 2, and it opens upwards because the coefficient of x^2 is positive (a = 1). The lowest point on the graph (the vertex) is at Y = 3. As we move away from the vertex in either direction along the x-axis, the Y values increase.