Question

Дана функция y=-x^2-х+12a) Найдите значения функции f(3),f(-5)

Answer 1

Ответ:

f(3) = 0

f(- 5) = - 8

Пошаговое объяснение:

y = f(x)

y = - x² - x + 12

f(3) = - 3² - 3 + 12 = - 9 - 3 + 12 = 0

f(-5) = - (- 5)² - (- 5) + 12 = - 25 + 5 + 12 = - 8

Answer 2

To find the values of the function $f(x) = -x^2 - x + 12$ at $x = 3$ and $x = -5$, simply substitute these values into the function:

a) $x = 3$ $f(3) = -(3)^2 - 3 + 12$ $f(3) = -9 - 3 + 12$ $f(3) = 0$

b) $x = -5$ $f(-5) = -(-5)^2 - (-5) + 12$ $f(-5) = -25 + 5 + 12$ $f(-5) = -8$

Therefore, $f(3) = 0$ and $f(-5) = -8$.