Question

1)7a+7b,если a+b=14, 2)m•17+n•17, m+n=1000,3) k•9+9L,k+l=12 ,4) 4c-4d, c - d =125, 5)x•23-23y , x=y=4, 6) 56p-r •56, p-r=11.

Answer 1

$7a + 7b = 7(a + b) = 7 \times 14 = 98$
$m \times 17 + n \times 17 = 17(m + n) = 17 \times 1000 = 17000$
$k \times 9 + 9l = 9(k + l) = 9 \times 12 = 108$
$4c - 4d = 4(c - d) = 4 \times 125 = 500$
$x \times 23 - 23y = 23(x - y) = 23 \times 0 = 0$
$56p - r \times 56 = 56(p - r) = 56 \times 11 = 616$

Answer 2

To simplify each expression, we'll use the given conditions to substitute the values. Let's solve each one:

1. Given a + b = 14, we need to find the value of 7a + 7b: 7a + 7b = 7(a + b) = 7(14) = 98.

2. Given m + n = 1000, we need to find the value of m•17 + n•17: m•17 + n•17 = 17(m + n) = 17(1000) = 17000.

3. Given k + l = 12, we need to find the value of k•9 + 9l: k•9 + 9l = 9(k + l) = 9(12) = 108.

4. Given c - d = 125, we need to find the value of 4c - 4d: 4c - 4d = 4(c - d) = 4(125) = 500.

5. Given x = 4 and y = 4, we need to find the value of x•23 - 23y: x•23 - 23y = 4•23 - 23•4 = 92 - 92 = 0.

6. Given p - r = 11, we need to find the value of 56p - r • 56: 56p - r • 56 = 56(p - r) = 56(11) = 616.

So, the simplified values are:

1. 7a + 7b = 98.
2. m•17 + n•17 = 17000.
3. k•9 + 9l = 108.
4. 4c - 4d = 500.
5. x•23 - 23y = 0.
6. 56p - r • 56 = 616.