Question

1) 20/40 * 2/4 2) 2/3 - 3/8 3)4/7 + 3/5 4)3/7 : 1/21 + (3/5 - 1/8)

Answer 1

Поймёте не поймёте не знаю но точно все правильно!

Answer 2

Let's solve each of the expressions step by step:

1. $\frac{20}{40} \times \frac{2}{4}$ First, simplify each fraction: $\frac{20}{40} = \frac{1}{2}$ and $\frac{2}{4} = \frac{1}{2}$

Now, multiply the fractions: $\frac{1}{2} \times \frac{1}{2} = \frac{1}{4}$

So, the result is $\frac{1}{4}$.

2. $\frac{2}{3} - \frac{3}{8}$ To subtract fractions, we need a common denominator, which is 24 in this case.

Rewrite the fractions with the common denominator: $\frac{2}{3} = \frac{16}{24}$ and $\frac{3}{8} = \frac{9}{24}$

Now, perform the subtraction: $\frac{16}{24} - \frac{9}{24} = \frac{16 - 9}{24} = \frac{7}{24}$

So, the result is $\frac{7}{24}$.

3. $\frac{4}{7} + \frac{3}{5}$ To add fractions, we need a common denominator, which is 35 in this case.

Rewrite the fractions with the common denominator: $\frac{4}{7} = \frac{20}{35}$ and $\frac{3}{5} = \frac{21}{35}$

Now, perform the addition: $\frac{20}{35} + \frac{21}{35} = \frac{20 + 21}{35} = \frac{41}{35}$

Since $\frac{41}{35}$ is an improper fraction (the numerator is greater than the denominator), we can write it as a mixed number: $1 \frac{6}{35}$.

So, the result is $1 \frac{6}{35}$.

4. $\frac{3}{7} : \frac{1}{21} + \left(\frac{3}{5} - \frac{1}{8}\right)$ To divide fractions, we can multiply by the reciprocal of the divisor.

First, solve the division: $\frac{3}{7} \div \frac{1}{21}$. Dividing by a fraction is the same as multiplying by its reciprocal, so: $\frac{3}{7} \times \frac{21}{1} = \frac{63}{7} = 9$

Now, we have: $9 + \left(\frac{3}{5} - \frac{1}{8}\right)$

To simplify $\frac{3}{5} - \frac{1}{8}$, we need a common denominator, which is 40 in this case.

Rewrite the fractions with the common denominator: $\frac{3}{5} = \frac{24}{40}$