Question

X^2 + x - 5=0 x1=? x2 =?​

Answer 1

x²+x-5=0

D=1+20= 21

x1= (-1+√21)/2

x2= (-1-√21)/2

Answer 2

Ответ:

Пошаговое объяснение:

Answer 3

To find the values of x₁ and x₂, we can use the quadratic formula. The quadratic formula is given by:

x = (-b ± √(b² - 4ac)) / 2a

where, for the quadratic equation ax² + bx + c = 0:

a = 1 (coefficient of x²) b = 1 (coefficient of x) c = -5 (constant term)

Now, let's calculate x₁ and x₂:

x₁ = (-1 + √(1² - 4 * 1 * -5)) / 2 * 1 x₁ = (-1 + √(1 + 20)) / 2 x₁ = (-1 + √21) / 2 x₁ ≈ 1.791

x₂ = (-1 - √(1² - 4 * 1 * -5)) / 2 * 1 x₂ = (-1 - √(1 + 20)) / 2 x₂ = (-1 - √21) / 2 x₂ ≈ -2.791

So, the approximate values of x₁ and x₂ are x₁ ≈ 1.791 and x₂ ≈ -2.791.