Question

..×... =...+21 вставь пропущенные числа

Answer 1

3×7=0+21♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡удачи

Answer 2

Ответ:

5×7 = 14+21

Пошаговое объяснение:

5×7 = 14+21

35 = 35

Answer 3

To solve the equation "..×... = ... + 21" and find the missing numbers, we can start by understanding the pattern in the equation.

Let's represent the missing digits with letters: AB × CD = EF + 21

Since we are dealing with a multiplication and addition, we need to find two-digit numbers that satisfy the equation.

To make the multiplication result end with '1' (in EF + 21), the last digit of the second factor (CD) must be either 1 or 6. If the last digit of CD is 1, then the last digit of the first factor (AB) must be 9 to make it end with '1' after multiplication.

Let's try with CD = 11 and AB = 91: 91 × 11 = 1001

However, this doesn't satisfy the addition part of the equation since 1001 + 21 = 1022, and we need it to be EF + 21.

Let's try CD = 16 and AB = 96: 96 × 16 = 1536

Now, this works for the multiplication part. Let's check the addition part: 1536 + 21 = 1557

So, the missing numbers are AB = 96 and CD = 16: 96 × 16 = 1536 + 21

The equation is now balanced.