Question

Решить уравнение (x+5)^2=25 ​

Answer 1

Пошаговое объяснение:

(х + 5)² = 25,

(х + 5)² = 5²,     (х + 5)² = (-5)²,

х + 5 = 5,           х + 5 = -5,

х = 5 - 5,            х = -5 - 5,

х1 = 0,                х2 = -10,

или:

(х + 5)² = 25,

х² + 10х + 25 = 25,

х² + 10х + 25 - 25 = 0,

х² + 10х = 0,

х * (х + 10) = 0,

х1 = 0,    х + 10 = 0,

             х2 = -10

Answer 2

Пошаговое объяснение:

(x+5)² = 25 = 5²

x+ 5 = 5

x = 0 - ответ

Answer 3

To solve the equation $(x + 5)^2 = 25$, you'll need to isolate $x$ and find its possible values. Here's the step-by-step solution:

Step 1: Expand the left side of the equation: $(x + 5)^2 = (x + 5)(x + 5) = x^2 + 10x + 25$

Step 2: Now, the equation becomes: $x^2 + 10x + 25 = 25$

Step 3: Subtract 25 from both sides to get the equation in standard quadratic form: $x^2 + 10x = 0$

Step 4: Factor out the common term $x$ from the left side: $x(x + 10) = 0$

Step 5: Now, use the zero product property, which states that if the product of two factors is zero, then at least one of the factors must be zero. So, set each factor to zero and solve for $x$:

1. $x = 0$
2. $x + 10 = 0$

Solving the second equation for $x$: $x + 10 = 0$ Subtract 10 from both sides: $x = -10$

So, the two solutions to the equation are $x = 0$ and $x = -10$.