Question

1/3x > 2; 2-7x>0 ; 6(y-1,5)-3,4>4y-2,4​

Answer 1

надеюсь помогла/////

Answer 2

Ты в интернете набери этот пример по действиям и всё

Answer 3

To solve the inequalities, let's take them one by one:

1. $\frac{1}{3}x > 2$

To isolate x, we can multiply both sides by 3 (remembering to flip the inequality sign when multiplying by a negative number):

$x > 2 \times 3$

$x > 6$

So the solution for this inequality is $x > 6$.

2. $2 - 7x > 0$

First, let's move 2 to the other side by subtracting it from both sides:

$-7x > -2$

Next, divide both sides by -7 (remembering to flip the inequality sign again):

$x < \frac{-2}{-7}$

$x < \frac{2}{7}$

So the solution for this inequality is $x < \frac{2}{7}$.

3. $6(y-1.5) - 3.4 > 4y - 2.4$

First, distribute the 6:

$6y - 9 - 3.4 > 4y - 2.4$

Next, move all terms with y to one side by subtracting $4y$ from both sides:

$6y - 4y - 9 - 3.4 > -2.4$

Simplify:

$2y - 9 - 3.4 > -2.4$

Now, combine constants:

$2y - 12.4 > -2.4$

Next, move the constant term to the other side by adding 12.4 to both sides:

$2y > -2.4 + 12.4$

$2y > 10$

Finally, isolate y by dividing both sides by 2:

$y > \frac{10}{2}$

$y > 5$

So the solution for this inequality is $y > 5$.

To summarize the solutions:

1. $x > 6$
2. $x < \frac{2}{7}$
3. $y > 5$