Question

3x-5(12-6x)=-8,5 -12-2,3*(6,5-7x)=13,2 8*(2x-5)=12,3x-68 СРОЧНО!!!!!

Answer 1

3x-5(12-6x)=-8,5

3х-60+30х=-8,5

33х=-8,5+60

33х=51,5

х=51 1/2:33=103/2*1/33=1 37/66

-12-2,3*(6,5-7x)=13,2

-12-14,95+16,1х=13,2

16,1х=40,15

х=40,15:16,1= 40 15/100:16 1/10=(4015*10)/100*161=4015/1610=2 795/1610=2 159/322

8*(2x-5)=12,3x-68

16х-40=12,3х-68

3,7х=-28

х=-28:3 7/10=-28*10/37=-280/37=-7 21/37

Answer 2

Sure, I can help you solve these equations. Let's tackle them one by one:

1. 3x - 5(12 - 6x) = -8.5

Step 1: Distribute the -5 across the parentheses: 3x - 5 * 12 + 5 * 6x = -8.5

Step 2: Simplify the equation: 3x - 60 + 30x = -8.5

Step 3: Combine like terms: 33x - 60 = -8.5

Step 4: Move the constant term to the right side by adding 60 to both sides: 33x = -8.5 + 60

Step 5: Simplify: 33x = 51.5

Step 6: Divide both sides by 33 to isolate x: x = 51.5 / 33 x ≈ 1.56

So, the solution to the first equation is x ≈ 1.56.

2. -12 - 2.3 * (6.5 - 7x) = 13.2

Step 1: Distribute the -2.3 across the parentheses: -12 - 2.3 * 6.5 + 2.3 * 7x = 13.2

Step 2: Simplify the equation: -12 - 14.95 + 2.3x = 13.2

Step 3: Combine like terms: 2.3x - 26.95 = 13.2

Step 4: Move the constant term to the right side by adding 26.95 to both sides: 2.3x = 13.2 + 26.95

Step 5: Simplify: 2.3x = 40.15

Step 6: Divide both sides by 2.3 to isolate x: x = 40.15 / 2.3 x ≈ 17.46

So, the solution to the second equation is x ≈ 17.46.

3. 8 * (2x - 5) = 12.3x - 68

Step 1: Distribute the 8 across the parentheses: 8 * 2x - 8 * 5 = 12.3x - 68

Step 2: Simplify the equation: 16x - 40 = 12.3x - 68

Step 3: Move the 12.3x term to the left side by subtracting 12.3x from both sides: 16x - 12.3x - 40 = -68

Step 4: Combine like terms: 3.7x - 40 = -68

Step 5: Move the constant term to the right side by adding 40 to both sides: 3.7x = -68 + 40

Step 6: Simplify: 3.7x = -28

Step 7: Divide both sides by 3.7 to isolate x: x = -28 / 3.7 x ≈ -7.57

So, the solution to the third equation is x ≈ -7.57.

Please double-check the solutions and equations to ensure accuracy, and let me know if you need any further assistance!