Question

1.{25-4(х+7)=х(1+у)-4-у(х+7) {у(6-х)+18=х(2-у)+24Найдите решение систем уравнений помогите пожалуйста ​ Смотреть ответ Участник Знаний Участник Знаний Ответ: х=3; у=2 Пошаговое объяснение: 25-4(х+7)=х(1+у)-4-у(х+7) 25-4х-28=х+ху-4-ху-7у -3-4х=х-4-7у х+4х-7у=4-3 5х-7у=1 5х=1+7у х=(1+7у)/5 у(6-х)+18=х(2-у)+24 6у-ху+18=2х-ху+24 6у=2х-ху+24+ху-18 6у=2х+6 6у=2(1+7у)/5 +6 6у=(2+14у+30)/5 6у×5=32+14у 30у-14у=32 16у=32 у=32/16=2 х=(1+7×2)/5=(1+14)/5=15/5=3

Answer 1

To verify the solution given, let's substitute the values of x and y back into the original system of equations and check if both equations hold true.

The given system of equations is:

1. 25 - 4(x + 7) = x(1 + y) - 4 - y(x + 7)
2. y(6 - x) + 18 = x(2 - y) + 24

The solution provided is x = 3 and y = 2.

1. For x = 3 and y = 2:

   25 - 4(3 + 7) = 3(1 + 2) - 4 - 2(3 + 7) 25 - 4(10) = 3(3) - 4 - 2(10) 25 - 40 = 9 - 4 - 20 -15 = -15

   The first equation is true.

2. For x = 3 and y = 2:

   y(6 - x) + 18 = x(2 - y) + 24 2(6 - 3) + 18 = 3(2 - 2) + 24 2(3) + 18 = 3(0) + 24 6 + 18 = 0 + 24 24 = 24

   The second equation is also true.

Since both equations are true when x = 3 and y = 2, the solution is verified.

Therefore, the correct solution to the system of equations is x = 3 and y = 2.