Question

2^4-x<=8 помогите решить !!!!!!

Answer 1

2^(4-х) ≤8

2^(4-х) ≤2³

4-х≤3

-х≤3-4

-х≤-1

Х≥1

Х€ [1, +∞)

Answer 2

${2}^ {4 - x} \leqslant 8 \\ {2}^{4 - x} \leqslant {2}^{3} \\ 4 - x \leqslant 3 \\ - x \leqslant - 1 \\ x \geqslant 1$

Ответ: [1; +бесконечность).

Answer 3

Sure, I'd be happy to help you solve the inequality $2^4 - x \leq 8$.

Step 1: Simplify the left-hand side (LHS) of the inequality: $2^4$ means $2$ raised to the power of $4$, which is $2 \times 2 \times 2 \times 2 = 16$. So, the inequality becomes: $16 - x \leq 8$.

Step 2: Move the constant term to the other side of the inequality: To do this, we subtract $8$ from both sides of the inequality: $16 - 8 - x \leq 8 - 8$, which simplifies to: $8 - x \leq 0$.

Step 3: Isolate the variable (x) term: To isolate $x$, we subtract $8$ from both sides of the inequality: $8 - 8 - x - 8 \leq 0 - 8$, which simplifies to: $-x \leq -8$.

Step 4: Divide by -1 (since we're dividing by a negative number, the inequality sign will flip): When we divide by -1, we have to flip the inequality sign: $x \geq 8$.

So, the solution to the inequality is $x \geq 8$. This means any value of $x$ greater than or equal to $8$ will make the inequality true.