Question

X+3/12=4/3. 7x=x+25 0,4x-6=0,6x-9 3x+16=9-10x

Answer 1

Ответ:

Пошаговое объяснение:

X+3/12=4/3

Х=4/3-3/12

Х=16/12-3/12

Х=13/12=1 1/12

7x=x+25

7х-х=25

6х=25

Х=25/6

Х=4 1/6

0,4x-6=0,6x-9

0,4х-0,6х=6-9

-0,2х=-3

Х=-3:(-0,2)

Х=15

3x+16=9-10x

3х+10х=9-16

13х=-7

Х=-7/13

Answer 2

Let's solve each equation step by step:

1. $X+\frac{3}{12}=\frac{4}{3}$

To start, let's simplify the fractions: $X + \frac{1}{4} = \frac{4}{3}$

To get rid of the fraction, we can multiply both sides by 4: $4X + 1 = \frac{16}{3}$

Now, isolate X by subtracting 1 from both sides: $4X = \frac{16}{3} - 1$

Simplify the right side of the equation: $4X = \frac{16 - 3}{3}$ $4X = \frac{13}{3}$

Finally, divide by 4 to solve for X: $X = \frac{13}{3} \div 4$ $X = \frac{13}{3} \times \frac{1}{4}$ $X = \frac{13}{12}$

So, the solution is $X = \frac{13}{12}$.

2. $7X = X + 25$

To solve for X, let's isolate it on one side of the equation. First, subtract X from both sides: $7X - X = X + 25 - X$

Simplify both sides: $6X = 25$

Now, divide by 6 to find the value of X: $X = \frac{25}{6}$

So, the solution is $X = \frac{25}{6}$.

3. $0.4X - 6 = 0.6X - 9$

Let's solve for X by isolating it on one side. Start by subtracting $0.4X$ from both sides: $0.4X - 0.4X - 6 = 0.6X - 0.4X - 9$

This simplifies to: $-6 = 0.2X - 9$

Now, add 9 to both sides: $-6 + 9 = 0.2X - 9 + 9$

Simplifies to: $3 = 0.2X$

To find the value of X, divide by 0.2: $X = \frac{3}{0.2}$

Now, simplify the right side: $X = 15$

So, the solution is $X = 15$.

4. $3X + 16 = 9 - 10X$

To solve for X, let's first get rid of the variable on one side. Start by adding $10X$ to both sides: $3X + 10X + 16 = 9 - 10X + 10X$

Simplifies to: $13X + 16 = 9$

Next, subtract 16 from both sides: $13X + 16 - 16 = 9 - 16$

Simplifies to: $13X = -7$

Finally, divide by 13 to find the value of X: $X = \frac{-7}{13}$

So, the solution is $X = \frac{-7}{13}$.

Please double-check the steps and answers to ensure accuracy. If you have any further questions or need additional explanations, feel free to ask!