Question

(2,5-5y)x(1,6-0,4y)=0

Answer 1

Ответ:

Фото прикреплено.

~•~•~•ZLOY_TIGROVSKIY~•~•~•

Answer 2

(2,5-5y) * (1,6-0,4y) = 0,

4 - у - 8у + 2у² = 0,

2у² - 9у + 4 = 0,

Д = (-9)² - 4*2*4 = 81 - 32 = 49,

х1 = (9 + 7) / 2*2 = 16/4 = 4,

х2 = (9 - 7) / 2*2 = 2/4 = 1/2   (или  0,5)

Answer 3

To solve the equation $(2,5-5y) \times (1,6-0,4y) = 0$, we set each factor to zero and solve for the values of $y$.

First, set the first factor to zero:

$2,5 - 5y = 0$

Now, solve for $y$:

$5y = 2,5$

$y = \frac{2,5}{5}$

$y = 0,5$

Next, set the second factor to zero:

$1,6 - 0,4y = 0$

Now, solve for $y$:

$0,4y = 1,6$

$y = \frac{1,6}{0,4}$

$y = 4$

So, the solutions for $y$ that satisfy the equation are $y = 0,5$ and $y = 4$.