Question

Y=2x квад +6x. парабола максимальный бал

Answer 1

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Answer 2

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Answer 3

To find the maximum value of the quadratic function y = 2x^2 + 6x, we can determine the vertex of the parabola. The vertex of a parabola in the form y = ax^2 + bx + c is given by the coordinates (-b/2a, f(-b/2a)), where f(x) represents the value of the function.

In this case, a = 2 and b = 6. We can substitute these values into the formula to find the x-coordinate of the vertex:

x = -b / (2a) x = -6 / (2 * 2) x = -6 / 4 x = -3/2

Now, substitute this x-coordinate back into the original function to find the corresponding y-coordinate:

y = 2(-3/2)^2 + 6(-3/2) y = 2(9/4) - 18/2 y = 9/2 - 18/2 y = -9/2

Therefore, the maximum value of the quadratic function y = 2x^2 + 6x is -9/2, which occurs at the x-coordinate -3/2.