Question

3с2+3=10с решить дескреминант​

Answer 1

Ответ:

15с2

Пошаговое объяснение:

сложно лалалалалалалалалалалаоаооа

Answer 2

Ответ:

3с^2+3-10с=0

3с^2-10с+3=0

д=(-10)^2-4*3*3=100-36=64

Answer 3

To solve the equation 3c^2 + 3 = 10c and find the discriminant, we first need to rearrange the equation into a quadratic form.

3c^2 + 3 = 10c

Subtracting 10c from both sides:

3c^2 - 10c + 3 = 0

Now we have a quadratic equation in the form of ax^2 + bx + c = 0, where a = 3, b = -10, and c = 3.

The discriminant (Δ) of a quadratic equation ax^2 + bx + c = 0 is given by the formula: Δ = b^2 - 4ac.

Let's calculate the discriminant for this equation:

Δ = (-10)^2 - 4 * 3 * 3 = 100 - 36 = 64

The discriminant (Δ) is equal to 64 in this case.

Now, depending on the value of the discriminant, we can determine the nature of the solutions:

1. If Δ > 0, there are two distinct real solutions.
2. If Δ = 0, there is one real solution (a repeated root).
3. If Δ < 0, there are no real solutions (two complex conjugate solutions).

Since the discriminant is Δ = 64, which is greater than zero, the equation has two distinct real solutions. However, to find the exact values of c, we need to solve the quadratic equation by factoring, completing the square, or using the quadratic formula.