Question

(15603+a) – 2 477=13978 1234–(326+p)=867

Answer 1

(15603+a) – 2 477=13978

15603 + а -2447 = 13978

а = 13978 - 15603 + 2447

а=822

1234–(326+p)=867

1234 - 326 - р = 867

1234 - 326 -867 = р

р= 41

Answer 2

To solve the equations, let's go step by step:

1. (15603 + a) - 2477 = 13978

To solve for 'a,' we'll simplify the equation by performing the necessary operations:

15603 + a - 2477 = 13978 a = 13978 - 15603 + 2477 a = -11148

Therefore, the value of 'a' is -11148.

2. 1234 - (326 + p) = 867

We'll solve for 'p' by simplifying the equation:

1234 - (326 + p) = 867 1234 - 326 - p = 867

• p = 867 - 1234 + 326
• p = -41

Therefore, the value of 'p' is 41.

So the solutions for the given equations are: a = -11148 p = 41