Question

3arccos(-1)-2arccos0+arccos

Answer 1

Ответ:

9$\pi$/4

Answer 2

To simplify the expression, let's use the trigonometric identity:

arccos(-x) = π - arccos(x)

We can rewrite the expression as follows:

3arccos(-1) - 2arccos(0) + arccos(x)

Since arccos(-1) is equal to π, and arccos(0) is equal to π/2, we can substitute those values into the expression:

3π - 2(π/2) + arccos(x)

Simplifying further:

3π - π + arccos(x)

2π + arccos(x)

So, the simplified expression is 2π + arccos(x).